(w-3)/(w^2-9)

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Solution for (w-3)/(w^2-9) equation: 


D( w )

w^2-9 = 0

w^2-9 = 0

w^2-9 = 0

1*w^2 = 9 // : 1

w^2 = 9

w^2 = 9 // ^ 1/2

abs(w) = 3

w = 3 or w = -3

w in (-oo:-3) U (-3:3) U (3:+oo)

(w-3)/(w^2-9) = 0

w-3 = 0 // + 3

w = 3

w in { 3} 

w belongs to the empty set

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